int_(a)^(b)(x^(n))/(x^(n)+(16-x)^(n))

If overset(b)underset(a)int (x^(n))/(x^(4)+(16-x)^(n))dx=6 , then

If I(m,n)=int_(0)^(1)x^(m-1)(1-x)^(n-1)dx,(m,n in I,m,n>=0),th epsilonI(m,n)=int_(0)^(oo)(x^(m-1))/((1+x)^(m-n))dxI(m,n)=int_(0)^(oo)(x^(m-1))/((1+x)^(m+n))dxI(m,n)=int_(0)^(oo)(x^(n-1))/((1+x)^(m+n))dxI(m,n)=int_(0)^(oo)(x^(n))/((1+x)^(m+n))dx

The value of int_(a)^(b)(x^(n-1)((n-2)x^(2)+(n-1)(a+b)x+nab))/((x+a)^(2)(x+b)^(2))dx is equal to :

The vlaue of int_(a)^(b)(x^(n-1)((n-2)x^(2)+(n-1)(a+b)x+nab))/((x+a)^(2)(x+b)^(2))dx is equal to :

Evaluate of each of the following integral: int_a^b(x^(1//n))/(x^(1//n)+(a+b-x)^(1/n))dx , \ ngeq2

If m,n in N, then the value of int_(a)^(b)(x-a)^(m)(b-x)^(n)dx is equal to

Let n in N such that n gt 1 . Statement-1: int_(oo)^(0) (1)/(1+x^(n))dx=int_(0)^(1) (1)/((1-x^(n))^(1//n))dx Statement-2: int_a^b f(x)dx=int_(a)^(b) f(a+b-x)dx

If int(dx)/(x^(2)(x^(n)+1)^((n-1)/(n)))=-(f(x))^((1)/(n))+C then f(x) is (A)1+x^(n)(B)1+x^(-n)(C)x^(n)+x^(-n)(D)x^(n)-x^(-n)