Consider the ten numbers `a r ,a r^2, a r^3, ..... ,a r^(10)dot` If their sum is 18 and the sum of their reciprocals is 6, then the product of these ten numbers is a.`81` b. `243` c. `343` d.` 324`

Let sum of ten numbers a, ar, ar^(2) , ... Ar^(9) is 18 and sum of their reciprocal is 6 then product of these ten numbers is.

If S be the sum,p the product and R the sum of the reciprocals of n terms of a G.P.,then ((S)/(R))^(n) is equal to

The sum and product of two numbers are 11 and 18 respectively. The sum of their reciprocals is

The sum and product of two numbers are 11 and 18 respectively. The sum of their reciprocals is

if S is the sum,P the product and R the sum of reciprocals of n terms in G.P. prove that P^(2)R^(n)=S^(n)

Find the sum of the products of the ten numbers +-1,+-2,+-3,+-4, and d+-5 taking two at a time.

If S be the sum P the product and R be the sum of the reciprocals of n terms of a GP then p^(2) is equal to S/R b.R/S c.(R/S)^(n) d.(S/R)^(n)

The ratio between a to digit number and the sum of the digits of that number is 4:1. If the digit in the unit’s place is 3 more than the digit in the ten’s place, then the number is a. 24 b. 63 c. 36 d. 96