sqrt(5+27-4x^(5))

sqrt(5x -4)

"int sqrt(5-4x^(2))*dx

int(dx)/(sqrt(4x^(2)+5))

The value if definite integral int_(3/2)^(9/4)[sqrt(2x-sqrt(5(4x-5)))+sqrt(2x+sqrt(5(4x-5)))] dx is equal to

int_(2)^(3)sqrt(2x-sqrt(5(4x-5)))+sqrt(2x+sqrt(5(4x-5)))dx Find the value of the definite integral

Using properties of proportion, solve for x : (i) (sqrt(x + 5) + sqrt(x - 16))/ (sqrt(x + 5) - sqrt(x - 16)) = (7)/(3) (ii) (sqrt(x + 1) + sqrt(x - 1))/ (sqrt(x + 1) - sqrt(x - 1)) = (4x -1)/(2) . (iii) (3x + sqrt(9x^(2) -5))/(3x - sqrt(9x^(2) -5)) = 5 .

The value of lim_(x rarr oo)(sqrt(4x^(2)+5x+8))/(4x+5)

Evaluate the following limit : (lim)_(x->-oo)(sqrt(4x^2+5x+8))/(4x+5)

If (sqrt(5 + x) + sqrt(5 - x))/(sqrt(5 + x) - sqrt(5 - x)) = 3 , then what is the value of x ?

int(dx)/(sqrt(4x^2-5))=