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int(0)^((pi)/(2))log cos xdx=(-pi)/(2)lo...

int_(0)^((pi)/(2))log cos xdx=(-pi)/(2)log2

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int_(0)^((pi)/(2))log(sinx)dx=int_(0)^((pi)/(2))log(cosx)dx=(pi)/(2)log.(1)/(2)

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Statement-1: int_(0)^(pi//2) x cot x dx=(pi)/(2)log2 Statement-2: int_(0)^(pi//2) log sin x dx=-(pi)/(2)log2