`8sintheta costheta. cos2theta cos 4theta=sinx=>x=`

If 8sin theta cos theta cos2theta cos4theta=sinx then x=

For any acute angle theta; Prove (i) 'tan theta = sintheta/costheta (ii) cot theta =cos theta/sintheta

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta) =

(sintheta+sin2theta)/(1+costheta+cos2theta)=?

(sintheta+sin 2theta)/(1+costheta+cos2theta)=

2-cos^(2)theta =3 sintheta costheta , sintheta ne cos theta , then the value of tan theta is

(sin3theta-cos3theta)/(sintheta+costheta)+1 =

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1