In a sample of H-atoms , electrons de-excite from a level 'n' to 1 . The total number of lines belonging to Balmer series are two . If the electrons are ionised from level 'n' by photons of energy 13 eV . Then the kinetic energy of the ejected photoelectrons will be :

Number of spectral lines falling Balmer series when electrons are de - excited from n^(th) shell will be given as

Number of spectral lines falling Balmer series when electrons are de - excited from n^(th) shell will be given as

A photon of energy 15 eV collision , H-atom gets ionised. The maximum kinetic energy of emitted electron is

If radiation corresponding to second line of "Balmer series" of Li^(+2) ion, knocked out electron from first excited state of H-atom, then kinetic energy of ejected electron would be:

If radiation corresponding to second line of "Balmer series" of Li^(+2) ion, knocked out electron from first excited state of H-atom, then kinetic energy of ejected electron would be:

If radiation correcsponding to second line of “Balmer series” of Li^(2+) ion, knocked out electron from first excited state of H-atom, then kinetic energy of ejected electron would be:

If radiation corresponding to second line of "Balmer series" of Li^(+2) ion, knocked out electron from first excited state of H-atom, then kinetic energy of ejected electron would be:

The total energy of an electron in the first excited state of hydrogen atom is -3.4eV. What is the kinetic energy of the electron in this state ?

Photons of equal energy were incident on two different gas samples. One sample containing H-atoms in the ground state and the other sample containing H-atoms in some excited state with a principle quantum number 'n'. The photonic beams totally ionise the H-atoms. If the difference in the kinetic energy of the ejected electrons in the two different cases is 12.75 eV . Then find the principal quantum number 'n' of the excited state.

Photons of equal energy were incident on two different gas samples. One sample containing H-atoms in the ground state and the other sample containing H-atoms in some excited state with a principle quantum number 'n'. The photonic beams totally ionise the H-atoms. If the difference in the kinetic energy of the ejected electrons in the two different cases is 12.75 eV . Then find the principal quantum number 'n' of the excited state.