[" 5) Ir "3tan theta=4],[" Find "(3sin theta+2cos theta)/(3sin theta-2cos theta)]

If 3 tan theta =4 , "evaluate "(3sin theta + 2 cos theta)/(3 sin theta - 2 cos theta ).

If 4tan theta=3, evaluate (4sin theta-cos theta+1)/(sin theta+cos theta-1)

If tan theta=(4)/(3), find the value of (5sin theta+2cos theta)/(3sin theta-cos theta)

If tan theta = 4/3 ,then the value of (3 sin theta + 2cos theta)/(3 sin theta - 2 cos theta) is

If theta lies in the first quadrant and 5tan theta=4 then (5sin theta-3cos theta)/(sin theta+2cos theta)=

If tan theta=1 then (8sin theta +5 cos theta)/(sin^3theta-2cos^3theta+7cos theta)=

If 4tan theta=3, the value of ((4sin theta-2cos theta)/(4sin theta+2cos theta)) is:

If 3tan theta=4, find the value of (4cos theta-sin theta)/(2cos theta+sin theta)

If 4 tan theta =3 , evaluate ((4 sin theta - 2cos theta +3)/(4 sin theta +2 cos theta -5))