`4z+3=6+2z`

Divide: 5x^3-15 x^2+25 x\ b y\ 5x 4z^3+6z^2-z\ b y-1/2z

The equations x-y+2z=4 3x+y+4z=6 x+y+z=1 have

(4+z-(3+2z))/(6) =(-z -3 (5-2))/(7) What is the value of z in the equation above ?

Divide: 5x^(3)-15x^(2)+25xby5x4z^(3)+6z^(2)-zby-(1)/(2)z9x^(2)y-6xy+12xy^(2)by-(3)/(2)xy

Given z_(1)+3z_(2)-4z_(3)=0 then z_(1),z_(2),z_(3) are

Divide: 5z^3-6z^2+7z\ \ by 2z (ii) sqrt(3)\ a^4+\ 2sqrt(3)\ a^3+3a^2-6a\ by 3a

Let z_(1),z_(2),z_(3),z_(4) are distinct complex numbers satisfying |z|=1 and 4z_(3) = 3(z_(1) + z_(2)) , then |z_(1) - z_(2)| is equal to

Let z_(1),z_(2),z_(3),z_(4) are distinct complex numbers satisfying |z|=1 and 4z_(3) = 3(z_(1) + z_(2)) , then |z_(1) - z_(2)| is equal to

The equation x-y+2z=4,3x+y+4z=6, x+y+z=1 have