If the relation between acceleration and time for an object is given by
`a=2t+4t^(2)`
Calculate the position of object from the origin at t = 4 s.

The relation between the acceleration and time for an object is given below. Calculate the velocity with which the object is moving at t = 1 s. a=3t-4t^(2)

The relation between the acceleration and time for an object is given below. Calculate the velocity with which the object is moving at t = 1 s. a=3t-4t^(2)

The velocity of an object is changing with time and relation is given by the following equation. v=2t+3t^(2) Calculate the position of the object from the origin at t = 2 s. Assume particle to be at origin at t = 0

The velocity of an object is changing with time and relation is given by the following equation. v=2t+3t^(2) Calculate the position of the object from the origin at t = 2 s. Assume particle to be at origin at t = 0

The velocity of an object is changing with time and relation is given by the following equation. v=2t+3t^(2) Calculate the position of the object from the origin at t=2s.

The displacement x of an object is given as a function of time x=2t+3t^(2) Calculate the instantaneous velocity of the object at t = 2 s

The displacement x of an object is given as a function of time x=2t+3t^(2) Calculate the instantaneous velocity of the object at t = 2 s

The displacement s of an object is given as a function of time t s=5t^(2)+9t Calculate the instantaneous velocity of object at t = 0.

The displacement s of an object is given as a function of time t s=5t^(2)+9t Calculate the instantaneous velocity of object at t = 0.

The relation between displacement & time of a body is S = (2t^3- 4t^2 + 3t) unit What will be the acceleration after 3s?