Home
Class 12
PHYSICS
A palen mirror placed along xy plane is ...

A palen mirror placed along xy plane is moving with velocity `-3hati+5hatk-4hatk.` A point in front of the plane mirror is moving with velocity `-2hati-4hatj+4hatk.` Find velocity of image
`[-2hati=14hatj+4hatk]`

Promotional Banner

Similar Questions

Explore conceptually related problems

A plane mirror is moving with velocity -2 hati - 3 hatj + 4hatk . A point object in front of the mirror move with a velocity -3 hati + 4 hatj -4hatk . There hat j is along the normal to the plane mirror and facing towards the object. Find velocity of image.

A plane mirror is moving with velocity -2 hati - 3 hatj + 4hatk . A point object in front of the mirror move with a velocity -3 hati + 4 hatj -4hatk . There hat j is along the normal to the plane mirror and facing towards the object. Find velocity of image.

A plane mirror is moving with velocity -2 hati - 3 hatj + 4hatk . A point object in front of the mirror move with a velocity -3 hati + 4 hatj -4hatk . There hat j is along the normal to the plane mirror and facing towards the object. Find velocity of image.

Find the sum of the vectors veca = -2hati+hatj-4hatk and vecb = 3hati-hatj+5hatk .

Find the image of a point having position vector, 3hati-2hatj+hatk in the plane vecr.(3hati-hatj+4hatk)=2

Find P,if veca=-2hati-hatj+2hatk and vecb=hati+phatj+hatk and vecaxxvecb=3hati+4hatj+5hatk .

Find the image of the point hati+3hatj+4hatk in the plane vecr.(2hati-hatj+hatk)+3=0 .

Find the image of the point whose position vector is hati+2hatj+3hatk in the plane vecr.(hati+2hatj+4hatk)=38 .

Find the distance of the point (2hati-hatj-4hatk) from the plane vecr.(3hati-4hatj+12hatk)=9 .

Find the equation of the plane through the point hati+4hatj-2hatk and perpendicular to the line of intersection of the planes vecr.(hati+hatj+hatk)=10 and vecr.(2hati-hatj+3hatk)=18.