Find the number of divisors of the number `N=2^3 .3^5 .5^7 .7^9` which are perfect squares.

The number of divisors of 7! is

The total number of divisors of the number N=2^(5).3^(4).5^(10).7^(6) that are of the form 4K+2, AAK in N is equal to

The number of odd divisor of the number N=2^(10). 3^5 .7^2, are 16 b. 17 c. 18 d. 20

Find the number of divisors of the number 2^(5)3^(5)5^(3)7^(3) of the form (4n+1),n in N uu{0}

Find the largest number of 3 digits which is a perfect square.

Find the greatest number of 5 digits which is a perfect square.

Find the whole number for which: n-7=5

Find the sum of n terms of the series 1.3.5+3.5.7+5.7.9+dots

Find the sum of divisors of 544 which are perfect squares.