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f(x^2+x)+2f(x^2-3x+2)=9x^2-15 xAAx in R...

`f(x^2+x)+2f(x^2-3x+2)=9x^2-15 xAAx in R` find `f(2016)` Find `f: RR->RR,` such that `f(x)+xf(1-x)=1+x AA x in RR,`

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