Find the area enclosed by `y=g(x),` x-axis, x=1 and x=37, where g(x) is inverse of `f(x)=x^(3)+3x+1`.

If the area enclosed by g(x),x=-3, x = 5 and x-axis where g(x) is the inverse f(x) = x^3 + 3x + 1 is A, then [A] is

If the area enclosed by g(x),x=-3,x=5 and x -axis where g(x) is the inverse f(x)=x^(3)+3x+1 is A, then [A] is

If g(x) is inverse function of f(x)=x^(3)+3x-3 then g'(1)=

The area enclosed by the parabola y=3(1-x^(2)) and the x-axis is

The area the region enclosed by f(x)=x^(3)-10x and g(x)=6x, x ge 0, y ge 0 is

Fill in the blanks Area enclosed by the curve y = x^(1//3) , the x-axis and the lines x= 1 and x= 8 is…….. .

Let f(x)=x^(3)+3x+2 and g(x) be the inverse of it.Find the area bounded by g(x) x-axis and the ordinate at x=2 and x=6 .