Show that the expression of the time period T of a simple pendulum of length l given by `T = 2pi sqrt((l)/(g))` is dimensionally correct

Explanation

Given, `T=2pisqrt((l)/(g))`
Dimensionally, `[T]=sqrt(L/[[LT^(-2)]])=[T]`
As in the above equation,the dimensions of both side are same. Therefore, the given formula is dimensionally correct.