The volumes of two bodies are measured to be `V_1 = (10.2+-0.02) cm^3 and V_2 = (6.4 +- 0.01)cm^3`. Calculate sum and difference in volumes with error limits.

Explanation

given, `V_(1)=(10.2pm0.02)cm^(3)` and `V_(2)=(6.4pm0.01)m^(3)`
`DeltaV=pm(DeltaV_(1)+DeltaV_(2))`
`=pm(0.02+0.01)cm^(3)=pm0.03 cm^(3)`
`V_(1)+V_(2)=(10.2+6.4)cm^(3)=16.6 cm^(3)`
and `V_(1)+V_(2)=(10.2-6.4)cm^(3)=3.8 cm^(3)`
Hence, sum of volumes= `(16.6pm0.03)cm^(3)`
and difference of volumes= `(3.8pm0.03)cm^(3)`