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The units of length, velocity and force ...

The units of length, velocity and force are doubled. Which of the following is the correct change in th other units?

A

Unit of time is doubled

B

Unit of mass is doubled

C

Unit of momentum is doubled

D

Unit of energy is doubled

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The correct Answer is:
To solve the problem, we need to analyze how the doubling of the units of length, velocity, and force affects other physical quantities, specifically mass, time, momentum, and energy. ### Step-by-step Solution: 1. **Understanding the Units**: - Length (L) is represented as [L]. - Velocity (V) is represented as [L][T]⁻¹ (length per time). - Force (F) is represented as [M][L][T]⁻² (mass times acceleration). 2. **Doubling the Units**: - If the unit of length is doubled, we denote this as 2L. - If the unit of velocity is doubled, we denote this as 2V. - If the unit of force is doubled, we denote this as 2F. 3. **Finding the Effect on Mass**: - The formula for force is given by \( F = m \cdot a \), where \( a \) is acceleration. - Acceleration can be expressed as \( a = \frac{V}{T} \). - If both length and velocity are doubled, we can analyze the relationship: - Since \( F \) is doubled and \( V \) is doubled, we can express mass as: \[ m = \frac{F}{a} = \frac{F}{\frac{V}{T}} = \frac{F \cdot T}{V} \] - Doubling \( F \) and \( V \) results in: \[ m' = \frac{2F \cdot T}{2V} = \frac{F \cdot T}{V} = m \] - Therefore, mass remains unchanged. 4. **Finding the Effect on Time**: - The time can be derived from the relationship: \[ T = \frac{L}{V} \] - If both \( L \) and \( V \) are doubled: \[ T' = \frac{2L}{2V} = \frac{L}{V} = T \] - Thus, time also remains unchanged. 5. **Finding the Effect on Momentum**: - Momentum (P) is given by \( P = m \cdot V \). - Since mass does not change and velocity is doubled: \[ P' = m \cdot (2V) = 2(m \cdot V) = 2P \] - Therefore, momentum is doubled. 6. **Finding the Effect on Energy**: - Energy (E) can be expressed as work done, which is \( E = F \cdot d \). - If both force and displacement (length) are doubled: \[ E' = (2F) \cdot (2L) = 4(F \cdot L) = 4E \] - Thus, energy is quadrupled. ### Summary of Changes: - Mass: No change - Time: No change - Momentum: Doubled - Energy: Quadrupled ### Final Answer: The correct changes in the other units are: - Mass: No change - Time: No change - Momentum: Doubled - Energy: Quadrupled

To solve the problem, we need to analyze how the doubling of the units of length, velocity, and force affects other physical quantities, specifically mass, time, momentum, and energy. ### Step-by-step Solution: 1. **Understanding the Units**: - Length (L) is represented as [L]. - Velocity (V) is represented as [L][T]⁻¹ (length per time). - Force (F) is represented as [M][L][T]⁻² (mass times acceleration). ...
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DC PANDEY-UNITS, DIMENSIONS & ERROR ANALYSIS -Check Point 1.1
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