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The radius of a thin wire is 0.16mm. The...

The radius of a thin wire is `0.16mm`. The area of cross section taking significant figures into consideration in square millimeter is

A

0.08

B

`0.080`

C

`0.0804`

D

`0.080384`

Text Solution

Verified by Experts

The correct Answer is:
B
`R`=0.16mm
Hence, `A=piR^(2)=(22)/(7)xx(0.16)^(2)=0.080384`
Since radius has two significant figure so answer also will have two significant figures.
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