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If the error in the measurement of momen...

If the error in the measurement of momentum of a particle is (+ 100%), then the error in the measurement of kinetic energy is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
Since error in measurement of momentum is + 100%.
`therefore" "p_(1)=p,p_(2)=2p`
`K_(1)=(p^(2))/(2m),K_(2)=((2p^(2)))/(2m)`
% in `K=((K_(2)-K_(1))/(K_(1)))xx100`
`=((4-1)/(1))xx100=300%`
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