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Measure of two quantites along with the precision of respective measuring instrument is `A = 2.5 ms^(-1) +- 0.5 ms^(-1)`
`B = 0.10 s +- 0.01s` The value of AB will be

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The correct Answer is:
A
Given, `A=2.5" ms"^(-1)pm0.5" ms"^(-1),B=0.10spm0.01s`
`x=AB`=(2.5)(0.10)=0.25 m
`(Deltax)/(x)=(DeltaA)/(A)+(DeltaB)/(B)`
`" "=(0.5)/(2.5)+(0.01)/(0.10)=(0.05+0.025)/(0.25)=(0.075)/(0.25)`
`Deltax`=0.075 = 0.08 m, rounding off to two significant figures.
`AB=(0.25pm0.08)" m"`
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