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The length of a strip measured with a me...

The length of a strip measured with a meter rod is `10.0 cm`. Its width measured with a vernier callipers is `1.00 cm`. The least count of the meter rod is `0.1 cm` and that of vernier callipers is `0.01 cm`. What will be the error in its area?

A

`pm13%`

B

`pm7%`

C

`pm4%`

D

`pm2%`

Text Solution

Verified by Experts

The correct Answer is:
D
Area of strip = `lb`
`therefore" "((DeltaA)/(A))xx100=((Deltal)/(l))xx100+((Deltab)/(b))xx100`
`" "=(0.1)/(10)xx100+(0.01)/(1)xx100=pm2%`
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