In terms of basic units of mass (M), len...

In terms of basic units of mass (M), length (L), time (T), and charge (Q), the dimensions of magnetic permeability of vacuum `(mu_0)` would be

`["MLQ"^(-2)]`

`["LT"^(-1)"Q"^(-1)]`

`["ML"^(2)"T"^(-1)"Q"^(-2)]`

`["LTQ"^(-1)]`

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The correct Answer is:

The force per unit length experienced due to two wires in which current in flowing in the same direction is given by
`(dF)/(dl)=(mu_(0))/(4pi)(2I_(1)I_(2))/(d)rArr(["M L T"^(-2)])/(["L"])=[mu_(0)](["A"^(2)])/(["L"])`
`rArr(["MLT"^(-2)])/(["L"])=mu_(0)[("Q"^(2))/("T"^(2)"L")]rArr mu_(0)=["MLQ"^(-2)]`

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