In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is

Options

A. 0.14
B. 0.1
C. 0.07
D. 0.04

Answer

A

Explanation

Here, `P=(a^(3)b^(2))/(cd)`
`therefore(DeltaP)/(P)xx100=((3Deltaa)/(a)+(2Deltab)/(b)+(Deltac)/(c)+(Deltad)/(d))xx100`
`" "=3(Deltaa)/(a)xx100+2(Deltab)/(b)xx100+(Deltac)/(c)xx100+(Deltad)/(d)xx100`
`" "=3xx1+2xx2+3+4`
`" "=3+4+3+4=14%`