Resolve horizontally and vertically a force `F= 8N` which makes an angle of `45^(@)` with the horizontal.

Options

A. 5
√
2
N
B. √
2
N
C. 5
√
2
N
D. 4
√
2
N

Answer

D

Explanation

Horizontal component of F is
`F_(H)=Fcos45^(@)`
`=(8)((1)/(sqrt(2)))=4sqrt(2)N`

and vertical component of F is
`F_(v)=Fsin45^(@)`
`=(8)((1)/(sqrt(2
)))`
`4sqrt(2)N`