If `vecA=4hati-3hatj` and `vecB=6hati+8hatj` then magnitude and direction of `vecA+vecB` will be

Options

A. `5,tan^(-1)(3//4)`
B. `5sqrt(5) ,tan^(-1)(1//2)`
C. `10, tan^(-1)(5)`
D. `25,tan^(-1)(3//4)`

Answer

B

Explanation

(b)` A+B =10hati +5hatj`
`therefore|A+B|=sqrt((10^(2)+(5)^(2))=5sqrt(5)`
Angle of (A+B) with Xasis ,`theta=tan^(-1)((5)/(10))=tan^(-1)((1)/(2))`