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Resultant of two vetors A and B is given...

Resultant of two vetors A and B is given by `|R|={|A|-|B|}.`angle between A and B will be

A

`90^(@)`

B

`180^(@)`

C

`0^(@)`

D

none of these

Text Solution

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The correct Answer is:
To find the angle between two vectors A and B given that the magnitude of their resultant R is given by the equation |R| = |A| - |B|, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: We know that the resultant of two vectors A and B is given by the equation: \[ |R| = |A| - |B| \] 2. **Use the Formula for the Magnitude of the Resultant**: The magnitude of the resultant of two vectors A and B, which makes an angle θ with each other, is given by: \[ |R| = \sqrt{|A|^2 + |B|^2 + 2|A||B|\cos\theta} \] 3. **Set the Two Expressions for |R| Equal**: Since both expressions represent the magnitude of the resultant, we can equate them: \[ \sqrt{|A|^2 + |B|^2 + 2|A||B|\cos\theta} = |A| - |B| \] 4. **Square Both Sides to Eliminate the Square Root**: Squaring both sides gives: \[ |A|^2 + |B|^2 + 2|A||B|\cos\theta = (|A| - |B|)^2 \] 5. **Expand the Right Side**: Expanding the right side: \[ (|A| - |B|)^2 = |A|^2 - 2|A||B| + |B|^2 \] 6. **Set the Equations Equal**: Now we have: \[ |A|^2 + |B|^2 + 2|A||B|\cos\theta = |A|^2 - 2|A||B| + |B|^2 \] 7. **Simplify the Equation**: Cancel out |A|^2 and |B|^2 from both sides: \[ 2|A||B|\cos\theta = -2|A||B| \] 8. **Divide by 2|A||B| (assuming |A| and |B| are not zero)**: \[ \cos\theta = -1 \] 9. **Find the Angle θ**: The angle θ for which cosθ = -1 is: \[ \theta = 180^\circ \] ### Final Answer: The angle between vectors A and B is \( 180^\circ \). ---

To find the angle between two vectors A and B given that the magnitude of their resultant R is given by the equation |R| = |A| - |B|, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: We know that the resultant of two vectors A and B is given by the equation: \[ |R| = |A| - |B| ...
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