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If (|a+b|)/(|a-b|)=1, then the angle bet...

If `(|a+b|)/(|a-b|)=1`, then the angle between `a` and `b` is

A

`0^(@)`

B

`45^(@)`

C

`90^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) Given `(|a+b|)/(|a-b|)=1`
`i.e |a+b|=|a-b|`
`Or a^(2)+b^(2)+2abcos theta=a^(2)+b^(2)-2abcostheta`
`therefore costheta =0^(@)Or theta=90^(@)`
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