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When a force F acs on a body of mass m t...

When a force F acs on a body of mass m the acceleration product in the body is a . If htree equal forces `F_(1)=F_(2)=F_(3)=F` act on the same body as shown in figure the accleration produced is

A

`(sqrt(2)-1)a`

B

`(sqrt(2)+1)a`

C

`sqrt(2)a`

D

a

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Accelertion `a=(F)/(m)`
Resultant of `F_(1)andF_(2)`will be
`F_(12)=sqrt(2F)`(in opposite directiomn o f`F_(3)`)
Now ,resultant of`F_(12)and F_(3)`will be ,
`F_("net")=(sqrt(2)-1)F`
`thereforea=(F_("net"))/(m)=(sqrt(2)-1)(F)/(m)=(sqrt(2)-1)a`
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