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The velocity of a particle is v=6hati+2h...

The velocity of a particle is `v=6hati+2hatj-2hatk` The component of the velocity parallel to vector `a=hati+hatj+2hatk` invector from is

A

`6hati +2hatj +2hatk`

B

`2hati +2hatj +2hatk`

C

`hati +hatj +hatk`

D

`6hati +2hatj +2hatk`

Text Solution

AI Generated Solution

The correct Answer is:
To find the component of the velocity vector \( \mathbf{v} = 6\hat{i} + 2\hat{j} - 2\hat{k} \) that is parallel to the vector \( \mathbf{a} = \hat{i} + \hat{j} + 2\hat{k} \), we can follow these steps: ### Step 1: Calculate the dot product of \( \mathbf{v} \) and \( \mathbf{a} \) The dot product \( \mathbf{v} \cdot \mathbf{a} \) is calculated as follows: \[ \mathbf{v} \cdot \mathbf{a} = (6\hat{i} + 2\hat{j} - 2\hat{k}) \cdot (\hat{i} + \hat{j} + 2\hat{k}) \] Calculating the dot product: \[ = 6 \cdot 1 + 2 \cdot 1 + (-2) \cdot 2 \] \[ = 6 + 2 - 4 = 4 \] ### Step 2: Calculate the magnitude of vector \( \mathbf{a} \) The magnitude of vector \( \mathbf{a} \) is given by: \[ |\mathbf{a}| = \sqrt{(1^2 + 1^2 + 2^2)} = \sqrt{1 + 1 + 4} = \sqrt{6} \] ### Step 3: Calculate the component of \( \mathbf{v} \) parallel to \( \mathbf{a} \) The component of \( \mathbf{v} \) parallel to \( \mathbf{a} \) can be calculated using the formula: \[ \text{Component of } \mathbf{v} \text{ parallel to } \mathbf{a} = \frac{\mathbf{v} \cdot \mathbf{a}}{|\mathbf{a}|^2} \mathbf{a} \] First, we need \( |\mathbf{a}|^2 \): \[ |\mathbf{a}|^2 = 6 \] Now substituting the values: \[ \text{Component of } \mathbf{v} \text{ parallel to } \mathbf{a} = \frac{4}{6} \mathbf{a} = \frac{2}{3} \mathbf{a} \] Substituting \( \mathbf{a} \): \[ = \frac{2}{3} (\hat{i} + \hat{j} + 2\hat{k}) = \frac{2}{3}\hat{i} + \frac{2}{3}\hat{j} + \frac{4}{3}\hat{k} \] ### Final Answer Thus, the component of the velocity \( \mathbf{v} \) parallel to the vector \( \mathbf{a} \) is: \[ \frac{2}{3}\hat{i} + \frac{2}{3}\hat{j} + \frac{4}{3}\hat{k} \] ---

To find the component of the velocity vector \( \mathbf{v} = 6\hat{i} + 2\hat{j} - 2\hat{k} \) that is parallel to the vector \( \mathbf{a} = \hat{i} + \hat{j} + 2\hat{k} \), we can follow these steps: ### Step 1: Calculate the dot product of \( \mathbf{v} \) and \( \mathbf{a} \) The dot product \( \mathbf{v} \cdot \mathbf{a} \) is calculated as follows: \[ \mathbf{v} \cdot \mathbf{a} = (6\hat{i} + 2\hat{j} - 2\hat{k}) \cdot (\hat{i} + \hat{j} + 2\hat{k}) ...
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