The position of object moving along an x-axis is given by `x=3t-4t^(2)+t^(3)`, where x is in meters and t in seconds. Find the position of the object at the following values of t : (i) 2s, (ii) 4s, (iii) What is the object's displacement between t = 0 s and t = 4 s ? and (iv) What is its average vvelocity for the time interval from t = 2 s to t = 4 ?

Explanation

To solve the problem step by step, we will follow the instructions given in the question.

### Given:
The position of the object is given by the equation:
\[ x(t) = 3t - 4t^2 + t^3 \]
where \( x \) is in meters and \( t \) is in seconds.

### Step 1: Find the position of the object at \( t = 2 \) seconds.
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