Home
Class 11
PHYSICS
The displacement of a particle starting ...

The displacement of a particle starting from rest (at `t = 0)` is given by `s = 6t^(2) - t^(3)`. The time in seconds at which the particle will attain zero velocity again, is

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
Displacement of the particle
`s = 6t^(2)-t^(3)`
Velocity of the particle
`upsilon=(ds)/(dt)=(d)/(dt)(6t^(2)-t^(3))`
`upsilon=12t-3t^(2)`
For `upsilon = 0 rArr 12t=3t^() rArr t=4s`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    DC PANDEY|Exercise Check point 3.3|10 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise Check point 3.4|15 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise Check point 3.1|10 Videos

  • MOTION

    DC PANDEY|Exercise Medical entrances gallery|19 Videos

  • PROJECTILE MOTION

    DC PANDEY|Exercise Level - 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

The displacement s of a particle at a time t is given bys =t^(3)-4t^(2)-5t. Find its velocity and acceleration at t=2 .

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

The displacement of a particle moving in a straight line is given by s=t^(3)-6t^(2)+3t+4 meters.The velocity when acceleration is zero is "

The displacement of a particle is given by y=(6t^2+3t+4)m , where t is in seconds. Calculate the instantaneous speed of the particle.

The speed(v) of a particle moving along a straight line is given by v=(t^(2)+3t-4 where v is in m/s and t in seconds. Find time t at which the particle will momentarily come to rest.

The displacement of a particle along an axis is described by equation x = t^(3) - 6t^(2) + 12t + 1 . The velocity of particle when acceleration is zero, is

The displacement of a particle executing S.H.M. is given by y = 10 sin [6t + (pi)/(3)] where y is in metres and t is in seconds. Then the initial displacement and velocity of the particle is

The displacement s of a moving particle at a time t is given by s=5+20t-2t^(2) . Find its acceleration when the velocity is zero.