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An insect crawls a distance distance of ...

An insect crawls a distance distance of 4 m along North in 10 s and then a distance of 3 m along East in 5 s. The average velocity of the insect is

A

`(7)/(15)ms^(-1)`

B

`(1)/(5)ms^(-1)`

C

`(1)/(3)ms^(-1)`

D

`(4)/(5)ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`upsilon_(av)=("Total displacement")/("Total time")=(sqrt((4)^(2)+(3)^(2)))/(10+5)=(1)/(3)ms^(-1)`
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