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The average velocity of a body moving wi...

The average velocity of a body moving with uniform acceleration after travelling a distance of `3.06 m` is `0.34 m s^(-1)`. If the change in velocity of the body is `0.18 ms^(-1)` during this time, its uniform acceleration is .

A

`0.01 ms^(-2)`

B

`0.02 ms^(-2)`

C

`0.03 ms^(-2)`

D

`0.04 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Time `("Distance")/("Average velocity")=(3.06)/(0.34)=9s`
Acceleration `=("change in velocity")/("Time")=(0.18)/(9)=0.02 m//s^(2)`
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