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The displacement x of a particle at time...

The displacement x of a particle at time t along a straight line is given by `x = alpha - beta t+gamma t^(2)`. The acceleraion of the particle is

A

`-beta`

B

`-beta+2gamma`

C

`2 gamma`

D

`-2gamma`

Text Solution

Verified by Experts

The correct Answer is:
C

`x=alpha-beta t+gamma t^(2)`
`upsilon=(dx)/(dt)=(d)/(dt)(alpha-beta t+gamma t^(2))=-beta+2gamma t`
`a =(d upsilon)/(dt)=(d)/(dt)(-beta+2gamma t)=2gamma`
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