Home
Class 11
PHYSICS
The distance traversed by a particle mov...

The distance traversed by a particle moving along a straight lne is given by `x = 180t+50t^(2)` metre. The acceleration of the particle is

A

`180 ms^(-2)`

B

`580 ms^(-2)`

C

`100 ms^(-2)`

D

`50 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`x=180t+50t^(2)`
`upsilon=(dx)/(dt)=180+100t`
`a=(d upsilon)/(dt)=100m//s^(2)`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    DC PANDEY|Exercise Check point 3.4|15 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise Check point 3.5|25 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise Check point 3.2|10 Videos

  • MOTION

    DC PANDEY|Exercise Medical entrances gallery|19 Videos

  • PROJECTILE MOTION

    DC PANDEY|Exercise Level - 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

The distance traversed by a particle moving along a straight line is given by x = 180 t + 50 t^(2) metre. Find the velocity at the end of 4s.

The displacement 'x' of a particle moving along a straight line at time t is given by x=a_(0)+a_(1)t+a_(2)t^(2) . The acceleration of the particle is :-

The displacement x of a particle at time t along a straight line is given by x = alpha - beta t+gamma t^(2) . The acceleraion of the particle is

The displacement x of a particle along a straight line at time t is given by x = a_(0) - a_(1) t + a_(2) t^(2) . The acceleration of the particle is -

The displacement x of a particle along a straight line at time t is given by x = a_(0) +a_(1)t + a_(2)t ^(2) . The acceleration of the particle is

The displacement of a particle moving along a straight line is given by s=3t^(3)+2t^(2)-10t. find initial velocity and acceleration of particle.

The displacement (in metre) of a particle moving along X-axis is given by x=18t+5t^(2) . The average acceleration during the interval t_(1)=2s and t_(2)=4s is