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The displacement (in metre) of a particl...

The displacement (in metre) of a particle moving along x-axis is given by `x=18t +5t^(2). Calculate (i) the instantaneous velocity `t=2 s` (ii) average velocity between `t=2 s` to `t=3 s` (iii) instantaneous acceleration.

A

`18 ms^(-2)`

B

`10 ms^(-2)`

C

`5 ms^(-2)`

D

`1 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`a=(d upsilon)/(dt)`
Here, `x=18t+5t^(2)`
`therefore upsilon (dx)/(dt)=(d)/(dt)(18t+5t^(2))=18+10t`
`rArr a=(d upsilon)/(dt)=(d)/(dt)(18+10t)=10m//s^(2)`
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