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A particle velocity changes from (2hat(i...

A particle velocity changes from `(2hat(i)+3hat(j))ms^(-1)` to `(2hat(i)-3hat(j))ms^(-1)` in 2 s. The acceleration in `ms^(-2)` is

A

`-(hat(i)+5hat(j))`

B

`(hat(i)+5hat(j))//2`

C

zero

D

`(-3hat(j))`

Text Solution

Verified by Experts

The correct Answer is:
D
`a=(v_(f)-v_(i))/(Delta t)=((2hat(i)-3hat(j))-(2hat(i)+3hat(j)))/(2)=(-6hat(j))/(2)=-3hat(j)ms^(-2)`
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