If a ball is thrown vertically upwards with speed `u`, the distance covered during the last `t` second of its ascent is

Options

A. `ut-(g t^(2)//2)`
B. `(u+g t)t`
C. `ut`
D. `g t^(2)//2`

Answer

D

Explanation

Let t second of upward journey = first t second of dowanward journey (with zero initial velocity)
`therefore` Desired distance `=(1)/(2)g t^(2)`