A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is `10 ms^-1` , then the maximum height attained by the stone is (`g= 10 ms^(-2)`)

Options

A. 16 m
B. 10 m
C. 20 m
D. 40 m

Answer

B

Explanation

`h=((10)^(2))/(2g)=5m`

`therefore` Total height = 2h = 10 m