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For a particle moving along a straight l...

For a particle moving along a straight line, the displacement x depends on time t as `x = alpha t^(3) +beta t^(2) +gamma t +delta`. The ratio of its initial acceleration to its initial velocity depends

A

only on `alpha` and `gamma`

B

only on `beta` and `gamma`

C

only on `alpha` and `beta`

D

only on `alpha`

Text Solution

Verified by Experts

The correct Answer is:
B

`upsilon=3alpha t^(2)+2beta t+gamma : upsilon_(t=0)=upsilon_(i)=gamma`
`a=6alpha t+2beta: a_(t=0)=a_(i)=2beta`
`therefore (upsilon_(i))/(a_(i))=(gamma)/(2beta)`
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