The distance time graph of a particle at time `t` makes angle `45^(@)` with respect to time axis. After `1s`, if makes angle `60^(@)` with respect to time axis. What is the acceleration of the particle?

Options

A. `sqrt(3)-1`
B. `sqrt(3)+1`
C. `sqrt(3)`
D. 1

Answer

A

Explanation

`upsilon_(i)` = slope of s-t graph = `tan45^(@) = 1 ms^(-1)`
`upsilon_(f)` = slope of s-t graph = `tan 60^(@)=sqrt(3)ms^(-01)`
Now `a_(av)=(upsilon_(f)-upsilon_(i))/(Delta t)=(sqrt(3)-1)/(1)=(sqrt(3)-1)` units