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The area under acceleration-time graph g...

The area under acceleration-time graph gives

A

distance travelled

B

change in acceleration

C

force acting

D

change in velocity

Text Solution

Verified by Experts

The correct Answer is:
D
The area under acceleration - time graph gives change in velocity.
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Area under a velocity-time graph gives

Draw the velocity-time graph for an object in uniform motion. Show that the area under the velocity-time graph gives the displacement of the object in the given time interval.

DC PANDEY-MOTION IN A PLANE-Check point 3.6
  1. Which of the following graph represents uniform motion

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  2. From the following displacement-time graph find out the velocity of a ...

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  3. The distance time graph of a particle at time t makes angle 45^(@) wit...

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  4. The graph between displacement and time for a particle moving with uni...

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  5. The v -t graph of a moving object is given in figure. The maximum acce...

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  6. The variation of velocity of a particle with time moving along a strai...

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  7. A lift is going up. The variation in the speed of the lift is as given...

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  8. The velocit-time graph of a body moving in a straight line is shown in...

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  9. The x-t equation is given as x=2t+1. The corresponding v-t graph is

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  10. Which of the following graph correctly represents velocity-time relati...

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  11. A particle is thrown vertically upwards with a velocity v. It returns ...

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  12. The following figure shows the velocity-time graph of a body. Accordi...

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  13. The velocity - time graph is shown in the figure, for a particle. The ...

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  14. The v-t plot of a moving object ios shown in the figure. The average v...

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  15. Which of the following graphs cannot possibly represent one dimensiona...

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  16. If the velocity v of particle moving along a straight line decreases l...

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  17. v^(2) versus s-graph of a particle moving in a straight line is shown ...

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  18. A graph between the square of the velocity of a particle and the dista...

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  19. The area under acceleration-time graph gives

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  20. A particle starts from rest at t= 0 and undergoes and acceleration (a...

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