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A ship X moving due North with speed v o...

A ship X moving due North with speed v observes that another ship Y is moving due West with speed v. The actual velocity of Y is

A

`sqrt(2)v` towards South-West

B

`sqrt(2)v` towards North-West

C

`sqrt(2)v` towards South-East

D

v towards North-East

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(x)=-upsilon hat(j)`

`therefore v_(Y)=v_(YX)+v_(X)=-upsilon hat(i)+upsilon hat(j)`
`therefore |v_(Y)|=sqrt(2)upsilon`
Direction of `v_(Y)` is North-West.
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