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A man is 25 m behind a bus, when bus sta...

A man is 25 m behind a bus, when bus starts accelerating at `2 ms^(-2)` and man starts moving with constant velocity of `10 ms^(-1)`. Time taken by him to board the bus is

A

2 s

B

3 s

C

4 s

D

5 s

Text Solution

Verified by Experts

The correct Answer is:
D
Displacement of man = displacement of bus + 25
or `10t=(1)/(2)xx2xx t^(2)+25` or `10t=t^(2)+25`
Solving this equation, we get t = 5 s.
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