Home
Class 11
PHYSICS
A ball is dropped from the top of a buil...

A ball is dropped from the top of a building 100 m high. At the same instant another ball is thrown upwards with a velocity of `40ms^(-1)` from the bottom of the building. The two balls will meet after.

A

5 s

B

`2.5 s`

C

2 s

D

3 s

Text Solution

Verified by Experts

The correct Answer is:
B
Relative acceleration = 0, relative velocity is `40 ms^(-1)` and relative separation is 100 m,
`therefore t=(100)/(40)=2.5 s`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    DC PANDEY|Exercise (A) Taking it together|75 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise (B) Meical entrance special format questions (Assertion and reason)|19 Videos

  • MOTION IN A PLANE

    DC PANDEY|Exercise Check point 3.6|20 Videos

  • MOTION

    DC PANDEY|Exercise Medical entrances gallery|19 Videos

  • PROJECTILE MOTION

    DC PANDEY|Exercise Level - 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

A ball is dropped from the top of a building 100 m high. At the same instant another ball is thrown upwards with a velocity of 40ms^(-1) form the bottom of the building. The two balls will meet after.

A ball is dropped from the top of a building of height 80 m. At same instant another ball is thrown upwards with speed 50 m/s from the bottom of the building. The time at which balls will meet is

A ball A is dropped from the top of a tower 500m high and at the same instant another ball b is projected upwards with the velocity of 100m/s. after how much time and where the two balls will meet?

A ball is dropped from top of a tower 250 m high. At the same time, another ball is thrown upwards with a velocity of 50 ms^(-1) from the ground. The time at which they cross each other is

A ball is dropped from a top of a 100 m high building. At the ssame time another ball is thrown up from the ground with a speed of 20ms^(-1) . At what time will the balls meet?

A ball is thrown downwards with a speed of 20 ms^(–1) from top of a building 150m high and simultaneously another ball is thrown vertically upwards with a speed of 30 ms^(–1) from the foot of the building. Find the time after which both the balls will meet - (g = 10 ms^(–2))

A particle is dropped from rest from the top of a building of height 100m. At the same instant another particle is projected upward from the bottom of the building What should be the speed of projection of the particle projected from the bottom of building so that the particle cross each other after 1s? Acceleration due to gravity is 10 m//s^(2) .

A stone is dropped from a height of 100m .At the same instant another stone is projected vertically upwards with velocity of 50ms^(-1) .If g=10ms^(-2) ,the height from the ground at which the 2 stones meet is

A ball is projected horizontally with a velocity of 5ms^(-1) from the top fo a building 19.6 m high. How long will th ball take to hit the ground ?