The displacement (x)-time (t) graph of a particle is shown in figure. Which of the following is correct ?

Options

A. Particle starts with zero velocity and variable acceleration
B. Particle starts with non-zero velocity and variable acceleration
C. Particle starts with zero velocity and uniform acceleration
D. Particle starts with non-zero velocity and uniform acceleration

Answer

A

Explanation

From the given graph, it is clear that
At `t = 0, (dx)/(dt) = 0`
`therefore` Velocity `upsilon =(dx)/(dt)=0` , at t = 0
As time passes `(dx)/(dt)` increases
`therefore` Velocity and hence acceleration changes.