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The velocity upsilon of a particle as a ...

The velocity `upsilon` of a particle as a function of its position (x) is expressed as `upsilon = sqrt(c_(1)-c_(2)x)`, where `c_(1)` and `c_(2)` are positive constants. The acceleration of the particle is

A

`c_(2)`

B

`-(c_(2))/(2)`

C

`c_(1)-c_(2)`

D

`(c_(1)+c_(2))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`upsilon^(2)=c_(1)-c_(2)x` comparing wiuth `upsilon^(2)=u^(2)+2as` we have
`a=-(c_(2))/(2)`
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