The displacement x of a particle in a straight line motion is given by `x=1-t-t^(2)`. The correct representation of the motion is

Options

A.
B.
C.
D.

Answer

B

Explanation

`(dx)/(dt)=upsilon=1-2t`
Comparing with `upsilon=u+at`, we have, `u=-1ms^(-1)` and
`a=-2ms^(-2)`
At t = 0, x = 1m. Then, u and a both are negative. Hence, x-coordinate of particle will go on decreasing.