A small block slides without friction down an iclined plane starting form rest. Let `S_(n)` be the distance traveled from time `t = n - 1` to `t = n`. Then `(S_(n))/(S_(n + 1))` is:

Options

A. `(2n-1)/(2n)`
B. `(2n+1)/(2n-1)`
C. `(2n-1)/(2n+1)`
D. `(2n)/(2n+1)`

Answer

C

Explanation

`S_(n)=(1)/(2)g cos theta(2n-1)`,
`S_(n+1)=(1)/(2)g cos theta {2(n+1)-1}`
`(S_(n))/(S_(n+1))=(2n-1)/(2n+1)`