A ball is thrown vertically upwards from the ground with a speed of `25.2 ms^(-1)`. How long does it take to reach its highest point and how high does it rise ? (Take `g=9.8 ms^(-2)`)

Options

A. `2.75s, 3.24 m`
B. `25.7s, 34.2 m`
C. `2.57s, 32.4 m`
D. `27.5s, 3.42 m`

Answer

C

Explanation

Given, upward velocity of ball `= 25.2 ms^(-1)` Height attained by the ball
`H=(u^(2))/(2g)=(25.2xx25.2)/(2xx9.8)=32.4m`
Now, time taken by the ball to attain `32.4 m` is
`t=(u)/(g)=(25.2)/(9.8)=2.57s`