A stone falls freely under gravity. It covered distances `h_1, h_2` and `h_3` in the first `5` seconds. The next `5` seconds and the next `5` seconds respectively. The relation between `h_1, h_2` and `h_3` is :

Options

A. `h_(1)=2h_(2)=3h_(3)`
B. `h_(1)=(h_(2))/(3)=(h_(3))/(5)`
C. `h_(2)=3h_(1)` and `h_(3)=3h_(2)`
D. `h_(1)=h_(2)=h_(3)`

Answer

B

Explanation

The relation between `h_(1), h_(2)` and `h_(3)` is
`h_(1)=(h_(2))/(3)=(h_(3))/(5)rArr h_(1):h_(2):h_(3)=1:3:5`